Penjelasan:
1. 8 cos 90 + 6 = 6 N
Ingat, gaya yang tegak lurus dengan gaya lain akan sama dengan 0.
2. Tidak diketahui sudutnya.
3. -10 cos 60 + 8 = (-5 akar 3 + 8) N
4. 3 cos 45 + 5 = (3/2 akar 2 + 5) N
5. 3 cos 60 + 4 = 3/2 + 4 = 5,5 N
6. 20 cos 60 + 40 = 10 + 40 = 50 m/s
Maaf apabila jawabannya kurang/tidak memuaskan dan semoga membantu.
[tex]fr = \sqrt{ {f1}^{2} + {f2}^{2} + 2f1f2 \cos( \alpha ) } [/tex]
1. F1 = 6 N F2 = 8 N alfa = 90°
[tex]fr = \sqrt{ {6}^{2} + {8}^{2} + 2(6)(8) \cos(90) } [/tex]
[tex]fr = \sqrt{36 + 64 + 0} = \sqrt{100} = 10 \: newton [/tex]
2. F1 = 16 N
F2 = 16 N
alfa = 120°
[tex]fr=\sqrt{ {16}^{2}+{16}^{2}+2(16)(16) \cos(120)} [/tex]
[tex]fr = \sqrt{256+ 256+ 512( - \frac{1}{2})} [/tex]
[tex]fr = \sqrt{256+256-256} = \sqrt{256} = 16 \: newton[/tex]
3. F1 = 8 N
F2 = 10 N
alfa = 120°
[tex]fr=\sqrt{ {8}^{2}+{10}^{2}+2(8)(10) \cos(120)} [/tex]
[tex]fr = \sqrt{64 + 100 + 160( - \frac{1}{2})} [/tex]
[tex]fr = \sqrt{84} = 2 \sqrt{21} = 9.165 \: newton[/tex]
4. F1 = 5 N
F2 = 3 N
alfa = 45°
[tex]fr = \sqrt{ {5}^{2} + {3}^{2} + 2(5)(3) \cos(45) } [/tex]
[tex]fr = \sqrt{25 + 9 + 30( \frac{1}{2} \sqrt{2)}}[/tex]
[tex]fr = \sqrt{34 + 15 \sqrt{2} } = \sqrt{55.21} = 7.43 \: newton [/tex]
5. F1 = 4N
F2 = 3N
alfa = 60°
[tex]fr = \sqrt{ {4}^{2} + {3}^{2} + 2(4)(3) \cos(60) } [/tex]
[tex]fr = \sqrt{16 + 9 + 24( \frac{1}{2})} [/tex]
[tex]fr = \sqrt{37} = 6.08 \: newton[/tex]
6. F1 = 40N
F2 = 20N
alfa = 60°
[tex]fr = \sqrt{ {40}^{2} + {20}^{2} + 2(40)(20) \cos(60) } [/tex]
[tex]fr = \sqrt{1600 + 400 + 1600( \frac{1}{2})} [/tex]
[tex]fr = \sqrt{2800} = 20 \sqrt{7} = 50.92 \: newton [/tex]
[answer.2.content]
