quizz...
3–x/3+x=(((1×3)×3÷3)×3)/27
x=???
3–x/3+x=(((1×3)×3÷3)×3)/27
x=???
Jawaban:
3-x/3 + x = (((1x3)x3:3)x3)/27
3-x/3+x = ((3x3:3)x3)/27
3-x/3+x = (3x3)/27
3-x/3+x = 9/27
3-x/3+x = 1/3
semua ruas di kalikan 3
9-x+3x = 1
9+2x =1
2x = 1-9
2x = -8
x = -4
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