quizzz...
f'(x)=x+x²×x
f(5)=???![]()
f'(x)=x+x²×x
f(5)=???
Jawaban:
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- ᥫDiketahui
f(5)
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- ᥫDitanya
f'(x) = x + x² × x
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- ᥫJawab
Dahulukan perkalian-!
f(x) = x + x² × x
f(5) = 5 + 5² × 5
f(5) = 5 + ( 5×5 ) × 5
f(5) = 5 + 25 × 5
f(5) = 5 + 125
f(5) = 130
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- ᥫKesimpulan
Maka hasil nya 130
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[tex]\huge\red{\boxed{\mathbb{ \colorbox{black}{\color{red}{ ..❦.. }}}}}[/tex]
[tex]f'(x) = x + x² × x[/tex]
[tex]f'(x) = x + x^{2+1}[/tex]
[tex]f'(x) = x + x³[/tex]
[tex]f'(x) = x^{1-1} + x^{3-1}[/tex]
[tex]f'(x) = x^{0} + x²[/tex]
[tex]f'(x) = 1 + x²[/tex]
[tex]f'(5) = 1 + 5²[/tex]
[tex]f'(5) = 1 + ( 5 × 5 )[/tex]
[tex]f'(5) = 1 + 25[/tex]
[tex]\bold{\underline{\red{\sf \tt f'(5) = 26}}} [/tex]
